Question

Помогите пожалуйста решить неравенство

Answer 1

Ответ:

Объяснение:

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Answer 2

$Cos(\frac{\pi }{6}-2x)<\frac{\sqrt{2} }{2}\\\\arcCos\frac{\sqrt{2} }{2}+2\pi n< \frac{\pi }{6}-2x<2\pi-arcCos\frac{\sqrt{2} }{2}+2\pi n,n\in Z\\\\\frac{\pi }{4}+2\pi n<\frac{\pi }{6}-2x<2\pi-\frac{\pi }{4}+2\pi n,n\in Z\\\\\frac{\pi }{4}+2\pi n<\frac{\pi }{6}-2x<\frac{7\pi }{4}+2\pi n,n\in Z\\\\\frac{\pi }{4}-\frac{\pi }{6} +2\pi n<\frac{\pi }{6}-2x-\frac{\pi }{6}<\frac{7\pi }{4}-\frac{\pi }{6} +2\pi n,n\in Z\\\\\frac{\pi }{12}+2\pi n<-2x<\frac{19\pi }{12}+2\pi n,n\in Z$

$\boxed{-\frac{19\pi }{24}+\pi n<x<-\frac{\pi }{24}+\pi n,n\in Z}$