Question

Помогите срочно пожалуйста

Answer 1

Ответ:

 $-2x^{2} +7x-6=0\\2x^{2} -7x+6=0\\D = (-7)^{2} - 4*2*6 = 1\\x_{1} =\frac{-(-7)+\sqrt{1} }{2*2} = \frac{8}{4} = 2 \\x_{2} =\frac{-(-7)-\sqrt{1} }{2*2} = \frac{6}{4} = \frac{3}{2} \\\\x^{2} +14x+49=0\\(x+7)^{2} = 0\\x +7 = 0\\x = -7\\\\(2x+1)^{2} = 3x+4\\4x^{2} +4x+1-3x-4=0\\4x^{2} +x-3=0\\D = 1^{2} - 4*4*(-3) = 49\\x_{1} =\frac{-1+\sqrt{49} }{2*4} =\frac{6}{8} = \frac{3}{4} \\ x_{2} =\frac{-1-\sqrt{49} }{2*4} = -\frac{8}{8} = -1$

9) не вместилось, пишу ниже:

(x+4)(2x-3)-(5x-6)(x-3)=10

2x²-3x+8x-12 -5x²+15x+6x-18 - 10 = 0

-3x²+26x-40 = 0

3x²-26x+40=0

D = (-26)² - 4×3×40 = 196

x1 = (26 - 14)/6 = 2

x2 =  (26 + 14)/6 = 20/3