Question

решить abs(x-1)+abs(x-2)+abs(x-3)+abs(x-4)+abs(x-5)=15(x+1)

Answer 1

Ответ:

bs*(ax-a+12bcsx²y-36bcsxy)

Пошаговое объяснение:

abs*(x-1)+6bs*(x-3)*2bscxy;

abs*(x-1)+12bs*(x-3)bscxy;

abs*(x-1)+12b²s²*(x-3)cxy;

abs*(x-1)12b²cs²xy*(x-3);

abs*(x-1)+12b²cs²xy*(x-3);

bs*(ax(x-1)*12bcsxy*(x-3));

bs*(a*(x-1)+12bcsxy*(x-3));

bs*(ax-a+12bcsxy*(x-3));