Question

cos[4x+pi/8]=0 Help pls

Answer 1

Ответ:

$\cos(4x + \frac{\pi}{8} ) = 0 \\ 4x + \frac{\pi}{8} = \frac{\pi}{2} + \pi \: n \\ 4x = \frac{3\pi}{8} + \pi \: n \\ x = \frac{3\pi}{32} + \frac{\pi \: n}{4}$

n принадлежит Z.