Question

Пж решите срочно даю 40 баллов

Answer 1

Ответ:

$\sin(30^{\circ} ) = \frac{1}{2} \\ \cos(30^{\circ} ) = \frac{ \sqrt{3} }{2} \\ tg(30^{\circ} ) = \frac{ \sin(30^{\circ} ) }{ \cos(30^{\circ} ) } = \frac{1}{2} \times \frac{ 2 }{ \sqrt{3} } = \\ = \frac{1}{ \sqrt{3} } = \frac{ \sqrt{3} }{3} \\ ctg(30^{\circ} ) = \frac{1}{tg(30^{\circ} )} = \sqrt{3}$

$\sin(60^{\circ} ) = \frac{ \sqrt{3} }{2} \\ \cos(60^{\circ} ) = \frac{1}{2} \\ tg(60^{\circ} ) = \frac{ \sin(60^{\circ} ) }{ \cos(60^{\circ} ) } = \frac{ \sqrt{3} }{2} \times 2 = \sqrt{3} \\ ctg(60^{\circ} ) = \frac{1}{tg(60^{\circ} ) } = \frac{ \sqrt{3} }{3}$

Треугольник АВС:

составим отношение:

$\sin(30^{\circ} ) = \frac{BC}{AB} = \frac{x}{2x} = \frac{1}{2}$

отсюда х = 1

$BC = 1 \\ AC = \sqrt{3} \\ AB = 2$