Предмет: Физика, автор: mrdonetskiy1

Помогите решить начинаяс ДАНО расписывая решение и ответ.
При каком напряжении в сети будет гореть полным накуалом электрическая лампа,ЕСЛИ НЕОБХОДИМАЯ СИЛА ТОКА 0,25 А, а сопротивление лампы 480 ом.

Ответы

Автор ответа: 555ai555

0

Ответ:

Объяснение:

I = 0,25 А

R = 480 ом

U = ?

U = I*R = 0.25*480 = 120 B

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