Question

помогите пожалуйста ​

Answer 1

$\displaystyle 3c^3-24=3(c^3-8)=3(c^3-2^3)=3(c-2)(c^2+2c+4)\\\\9a^2-16b^2=(3a)^2-(4b)^2=(3a-4b)(3a+4b)\\\\x^2-2xy+y^2=(x-y)^2=(x-y)(x-y)\\\\-5x^2+10x-5=-5(x^2-2x+1)=-5((x-1)^2=-5(x-1)(x-1)$