Question

Помогите пожалуйста)

Answer 1

Ответ:

Объяснение:

r1234 = R1/4 = 80/ 4 = 20 Ом

R5+R6 = R7+R8 = 20 Ом

r5678 = (R5+R6) / 2 = 20/2 = 10 Ом

r910 = R9*R10 / (R9+R10) = 5*20 / (5+20) = 4 Ом

R = r1234+r5678+r910 = 20+10+4 = 34 Ом

r12 = R1/2 = 10/2 = 5 Ом

r56 = R5*R6 / (R5+R6) = 4*6 / (4+6) = 2.4 Ом

R= r12+R3+R4+r56 = 5+5.4+3+2.4 = 15.8 Ом

R1+R2 = R4+R5 = R3 = 30 Ом

r12345 = R3/3 = 30/3 = 10 Ом

r67 = R6 / 2 = 100 / 2 = 50 Ом

R8+R9 = R10 = 40 Ом

r8910 = R10 / 2 = 40/2 = 20 Ом

R = r12345 + r67+r8910 = 10+50+20 = 80 Ом