Question

сколько грамм глицерина необходимо для образования 4 кг жира

Answer 1

         xКГ                                                         4КГ

H2COH-CHOH-CH2OH +3C17H35COOH=H2C-O-CO-C17H35

       m=92КГ                                            I

                                                            HC-O-CO-C17H35       +3H2O

                                                              I

                                                          H2C-O-CO-C17H35

                                                                    m=890КГ

X:92=4:890

X=0,4135КГ(413,5Г)