Question

Помогите пожалуйста вычислить. А и В делать не нужно.

Answer 1

7^log(7) 24 = 24   ( a^log(a) b = b)

log(5) 64 / log(5) 4 = log(4) 64 = 4 ( log(a) b = log(m) b / log(m) a)

log(16) log(9) 81 = log(16) log(9) 9^2 = log(2^4) 2 = 1/4 (log(a^n) b^m = m/n log(a) b)

log(3) log(7) 343 = log(3) log(7) 7^3 = log(3) 3 = 1

Answer 2

Объяснение:

a)

$log_{12}16+log_{12}9=log_{12}(16*9)=log_{12}144=log_{12}=12^2=2*log_{12}12=2.$

б)

$log_{11}363-log_{11}3=log_{11}\frac{363}{3}=log_{11}121=log_{11}11^2=2*log_{11}11=2.$

в)

$7^{log_724}=24.$

г)

$\frac{log_564}{log_54} =\frac{log_54^3}{log_54}=\frac{3*log_54}{log_54} =3.$

д)

$log_{16}log_981=log_{16}log_99^2=log_{16}(2*log_99)=log_{16}2=log_{2^4}2=\frac{1}{4}log_22=0,25.$

e)

$log_3log_7343=log_3log_77^3=log_3(3*log_77)=log_33=1.$