Question

Упрости выражения и найди его значения при m=1 и n=2 (m^3+6n^2)^2-(6n^2-m^3)^2

Answer 1

$(m^3+6n^2)^2-(6n^2-m^3)^2 = (m^3+6n^2-(6n^2-m^3))\cdot (m^3+6n^2+6n^2-m^3)=\\ \\ = (m^3+6n^2-6n^2+m^3)\cdot 12n^2=2m^3\cdot 12n^2=24m^3n^2 \\ \\ m=1; \ \ n=2 \\ \\ 24\cdot 1^3\cdot 2^2 =24\cdot 1 \cdot 4 =96$