Question

2. Вычислите предел функции:​

Answer 1

$\displaystyle \lim_{x \to \ 2} \frac{x-2}{(x-2)(x-3)}= \lim_{x \to \ 2} \frac{1}{x-3}= \lim_{x \to \ 2} \frac{1}{2-3} = -1$

$\displaystyle \lim_{x \to \ 7} \frac{x^2-4}{\sqrt{x-3}}= \lim_{x \to \ 7}\frac{49-4}{\sqrt{7-3}}=\frac{45}{2}=22.5$