Question

(х+3)³=х²(х+9) помогите пожалуйста решить

Answer 1

$(a + b)^{3} = a^{3} + 3a^{2} b + 3ab^{2} + b^{3}$
$x^{3} + 9 x^{2} + 27 x^{2} + 27- x^{3} - 9x^{2} = 0$
$27x = -27$
$x = -1$

Answer 2

$(x+3)^{3} = x^{2} (x+9)$
$x^{3}+3*3 x^{2} +3x* 3^{2}+ 3 ^{3}= x^{3}+9 x^{2}$
$x^{3}+9x^{2} +27x+ 27-x^{3}-9 x^{2}= 0$
$27x+ 27= 0$
$27x=-27$
$x=-1$