Question

решите срочно плиз дам 15 баллов

Answer 1

Ответ:

1.

$x {}^{3} + 6x {}^{2} + 11x + 6 = (x + 1)(x + 3)(x + 2) \\ x {}^{2n + 2} - 4n {}^{n + 2} + 4x {}^{2} = 4x {}^{2} + x {}^{2(n + 1)} - 4n {}^{n + 2} \\ - b {}^{4} - 4 = - (b {}^{2} - 2b + 2)(b {}^{2} + 2b + 2)$

2.

$\frac{x {}^{2} + 2x - 3}{x {}^{3} + 2x {}^{2} + 3x - 6} = \frac{x + 3}{x {}^{2} + 3x + 6}$

3.

$(m + 5q - 2b - 3p) {}^{2} = m {}^{2} + 10mq + 25q {}^{2} + 4b {}^{2} + 9p {}^{2} - 4bm - 20bq - 6mp - 30pq + 12bp$

4.

$x {}^{3} + 6x {}^{2} + 12x + 8 - 9x {}^{3} - 6x {}^{2} - x + 8x {}^{3} + 1 = 42 \\ 0 + 11x + 9 = 42 \\ 11x + 9 = 42 \\ 11x = 42 - 9 \\ 11x = 33 \\ x = 3$