Question

н 6 и н 5 пожалуйста

Answer 1

Ответ:

$s = a {}^{2} \\ s = (2 \sqrt{12} + \sqrt{3} ) { }^{2} = (4 \sqrt{3} + \sqrt{3} ) {}^{2} = (5 \sqrt{3} ) {}^{2} = 25 \times 3 = 75$

$(x + 3) {}^{2} + (x + 3)(x - 3) - \sqrt{3} ( \sqrt{12} x + \sqrt{3} ) = x { }^{2} + 6x + 9 + x {}^{2} - 9 - \sqrt{3} (2 \sqrt{3} x + \sqrt{3} ) = x {}^{2} + 6 x+ 9 + x {}^{2} - 9 - 6x - 3 = 2x {}^{2} - 3$