Question

log  в основание 2 умножить(4-3Х) = 6 НАВЕРХУ 3/ log числа 6 с основанием 2

Answer 1

log (3) 6 * log (36) 27 =
= 1/log(6) 3 * log(36) 27 =
= log(36) 27 / log(6) 3 =
= log(6^2) 27 /log(6) 3 =
= 1/2 * log(6) 27 / log(6) 3 =
= 1/2 * log(3) 27 =
= 1/2 * log(3) [3^3] =
= 1/2 * 3 = 3/2