Question

Помогите срочно!!! 25 баллов даю!!!

Answer 1

Ответ:

1

1.

$(3x - y)(9 {x}^{2} + 3xy + {y}^{2} )$

2.

$a(5a - b)(5a + b)$

3.

$- 3(x + 2) {}^{2}$

4.

$3a(b - 5) + 12(b - 5) = (b - 5)(3a + 12)$

5.

$( {a}^{2} - 25)(a {}^{2} + 25) = (a - 5)(a + 5)( {a}^{2} + 25)$

2.

$x( {x}^{2} - 1) - (x {}^{3} - 8) = {x}^{3} - x - {x}^{3} + 8 = 8 - x$

3.

1.

$(7m - n) + (7m - n)(7m + n) = (7m - n)(1 + 7m - n)$

2.

$(2x - y) {}^{2} - 16 = (2x - y - 4) (2x - y + 4)$

3.

${y}^{4} (x - 2) - y(x - 2) = (x - 2)( {y}^{4} - y)$

4.

$9 - (x + y) {}^{2} = (3 - x - y)(3 + x + y)$

4.

1.

$5x( {x}^{2} - 1) = 0 \\ 5x = 0 \\ x1 = 0 \\ {x}^{2} - 1 = 0 \\ {x}^{2} = 1 \\ x2 = - 1 \\ x3 = 1$

2.

$x(64 {x}^{2} - 16x + 1) = 0 \\ x1 = 0 \\ d = 256 - 256 = 0 \\ x2 = x3 = \frac{16 - 0}{2 \times 64} = \frac{16}{128} = \frac{1}{8}$

3.

${x}^{2} (x - 3) - 4(x - 3) = 0 \\ (x - 3)( {x}^{2} - 4) = 0 \\ x - 3 = 0 \\ x1 = 3 \\ {x}^{2} - 4 = 0 \\ {x}^{2} = 4 \\ x2 = - 2 \\ x3 = 2$

5.

$( {4}^{2} ) {}^{3} - {7}^{3 } = (16 - 7)(256 + 112 + 49) = 9 \times 417$

6.