Question

Помогите решить пожалуйста.Буду благодарен​

Answer 1

Ответ:

ниже

Пошаговое объяснение:

1. cos((x/2)+(π/6)) = √2/2

(x/2)+(π/6) = π/4

x/2 = π/12

x = π/6 = 30°

sin((x/3)+(π/2)) = 1

(x/3)+(π/2) = π/2

x/3 = 0

x = 0

2. (5/7)^(x+10) = (7/5)^(32x+1)

(5/7)^(x+10) = (5/7)^(-32x-1)

x+10 = -32x-1

33x = -11

x = -(1/3)

3. 5log_5(7) + log_√3(1/3) - log_0,125(5) = 5log_5(7) - 2 + (1/3)log_2(5) (!!!!!!!!!!!!!)

log_√3(1/3) = log_√3(3^-1) = -log_√3(3) = -log_3^(1/2)(3) =

= -2log_3(3) = -2

log_0,125(5) = log_2^-3(5) = -(1/3)log_2(5)

4. log_0,8(x-7) = log_0,8(x)

x-7 = x

-7 = 0

x не имеет корней