Question

Помогите пожалуйста!!!!!

Answer 1

$1)\frac{60}{Sin(-\frac{32\pi }{3})Cos(\frac{25\pi }{6})}=\frac{60}{-Sin(10\pi+\frac{2\pi }{3})Cos(4\pi +\frac{\pi }{6})}=-\frac{60}{Sin(\pi-\frac{\pi }{3})Cos\frac{\pi }{6}}=\\\\=-\frac{60}{Sin\frac{\pi }{3}Cos\frac{\pi }{6}}=-\frac{60}{\frac{\sqrt{3} }{2}*\frac{\sqrt{3}}{2}} =-\frac{60*4}{3}=\boxed{-80}$

$2)\frac{8}{\sqrt{3}} Cos\frac{\pi }{6}-7Sin\pi+\sqrt{2}Sin\frac{\pi }{4}+2Ctg\frac{3\pi }{4}=\frac{8}{\sqrt{3}}*\frac{\sqrt{3} }{2} -7*0+\sqrt{2}*\frac{1}{\sqrt{2} } +2*(-1)=\\\\=4-0+1-2=\boxed3$

$3)\frac{28}{Sin(-\frac{25\pi }{4})Cos(\frac{23\pi }{4})}=\frac{28}{-Sin(6\pi+\frac{\pi }{4})Cos(6\pi-\frac{\pi }{4})}=-\frac{28}{Sin\frac{\pi }{4}Cos\frac{\pi }{4}}=\\\\=-\frac{28}{\frac{\sqrt{2} }{2}*\frac{\sqrt{2}}{2}}=-\frac{28}{\frac{2}{4}}=-28*2=\boxed{-56}$