Question

$frac{6}{ x^{2} -1}- frac{2}{x-1}=2- frac{x+4}{x+1}$

Answer 1

$frac{6}{x^2-1}-frac{2}{x-1}=2-frac{x+4}{x+1}\ frac{6}{(x-1)(x+1)}-frac{2}{x-1}=2-frac{x+4}{x+1}\ 6-2(x+1)=2(x^2-1)-(x+4)(x-1)\ 6-2x-2=2x^2-2-x^2-3x+4\ x^2-x-2=0\ D=3^2\ x=2\ x=-1$
Ответ 2