Question

даю 30 баллов срочно

Answer 1

$(p^2-p+3)\cdot (24p^2+p-3)=\\\\=p^2\cdot 24p^2+p^2\cdot p+p^2\cdot (-3) -p\cdot 24p^2-p\cdot p-p\cdot (-3)+3\cdot 24p^2+3p+3\cdot (-3) = \\\\=24p^4+p^3-3p^2-24p^3-p^2+3p+72p^2+3p-9=24p^4-23p^3+68p^2+6p-9$

24 - 4; 23 - 3; 68 - 2; 6; 9