Question

Решите уравнение
2х2+3х/3-х=х-х/х-3

Answer 1

$\frac{2x^{2} +3x}{3-x} =x-\frac{x}{x-3} \;\;\;\;\;\;\;\;\;\;x\neq 3\\ \\ \frac{2x^{2} +3x}{3-x} =x+\frac{x}{3-x}\\ \\ \frac{x(2x+3)}{3-x} =\frac{x(3-x)+x}{3-x} \\ \\ \frac{x(2x+3)}{3-x} =\frac{3x-x^{2} +x}{3-x} \\ \\ \frac{x(2x+3)}{3-x} =\frac{4x-x^{2} }{3-x} \\ \\ x(2x+3)=x(4-x)\\ \\ 2x+3=4-x\\ \\ 2x+x=4-3\\\\3x=1\\\\x=\frac{1}{3}$