Question

$y = 4x {6} + \frac{ \sqrt{x} }{x {4} - 5 }$
найти производную функцию​

Answer 1

Ответ:

$y=2x^6+\dfrac{\sqrt{x}}{x^4-5}\\\\\\y'=12x^5+\dfrac{\dfrac{1}{2\sqrt{x}}\cdot (x^4-5)-4x^3\cdot \sqrt{x}}{(x^4-5)^2}=12x^5+\dfrac{x^4-5-8x^4}{\sqrt{x}\cdot (x^4-5)^2}=\\\\\\=12x^5-\dfrac{5+7x^4}{\sqrt{x}\cdot (x^4-5)^2}$