Question

АЛГЕБРА помогите пожалуйста​

Answer 1

$1. ~ \text{a}) ~ a^{3} + a^{2}b + a^{2} + ab = a(a^{2} + ab + a + b) = a((a^{2} + ab) + (a + b)) = \\= a(a(a+b) + (a+b)) = a(a+b)(a+1)$

$\text{b}) ~ 60 + 6ab - 30b - 12a = 6(10 + ab - 5b - 2a) = 6((10 - 5b) - (2a-ab)) =\\= 6(5(2-b) - a(2-b)) = 6(2-b)(5-a)$

$\text{c}) ~ 4xy + 12y - 4x - 12 = 4(xy + 3y - x - 3) = 4((xy + 3y) - (x + 3)) =\\= 4(y(x+3) - (x+3)) = 4(x+3)(y-1)$

$2. ~ \text{a}) ~ c^{2} + d - d^{2} + c = (c^{2} - d^{2}) + (c + d) = (c-d)(c+d) + (c+d) =\\= (c+d)(c-d +1)$

$\text{b}) ~ a - b + a^{2} - b^{2} = (a - b) + (a^{2} - b^{2}) = (a-b) + (a-b)(a+b) =\\= (a+b)(1 + a - b)$

Answer 2

1)а^3 + а^2b+а^2+аb
a•(a^2+ab+a+b)
a•(a•(a+b)+a+b)
a•(a+b)•(a+1)


2)60+6ab-30b-12a
6(10+ab-5b-2a)
6(5(2-b)-a•(-b+2))
6(2-b)•(5-a)




3)4xy+12y-4x-12
4(xy +3y-x-3)
4(y•(x+3)-(x+3))
4(x+3)•(y-1)





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