Question

Пожалуйста я умоляю

Answer 1

Объяснение:

$\frac{1}{64}a^3+b^3=(\frac{a}{4})^3+b^3=(\frac{a}{4}+b)*((\frac{a}{4})^2-\frac{a}{4}*b+b^2)=(\frac{a}{4} +b)*(\frac{1}{16}a^2-\frac{1}{4} ab+b^2)=\\=(0,25a+b)*(0,0625a^2-0,25ab+b^2).$

Answer 2

Ответ:

$\\ \frac{1}{64} a {}^{3} + b {}^{3} = \frac{1 {}^{3} }{4 {}^{3} } \times a {}^{3} + b {}^{3} =( \frac{1}{4} ) {}^{3} \times a {}^{3} + b {}^{3} = ( \frac{1}{4} a) {}^{3} + b {}^{3} = ( \frac{1}{4} a + b) \times(( \frac{1}{4} a {}^{} ) {}^{2} - \frac{1}{4} ab + b {}^{2} ) = ( \frac{1}{4} a + b) \times ( \frac{1}{16} a {}^{2} - \frac{1}{4} ab + b {}^{2} )$