Question

(y-4)^2=y^2-8+16 СРОЧНООО!!!!!!

Answer 1

$(y - 4) {}^{2} = y {}^{2} - 8 + 16$

$y {}^{2} - 8y + 16 = y {}^{2} - 8 + 16$

$- 8y = - 8$

$y = 1$