Question

помогите пожалуйста ​

Answer 1

Ответ:

а

$f'(x) = 3 \times 3 {x}^{2} - 8 \times 2x + 14 + 0 = \\ = 9 {x}^{2} - 16x + 14 \\ f'( - 1) = 9 + 16 + 14 = 39$

б

$f'(x) = \frac{( {x}^{2} - 5)'(x + 3) - (x + 3)'( {x}^{2} - 5)}{ {(x + 3)}^{2} } = \\ = \frac{2x(x + 3) - ( {x}^{2} - 5)}{ {(x + 3)}^{2} } = \\ = \frac{2 {x}^{2} + 6x - {x}^{2} + 5}{ {(x + 3)}^{2} } = \frac{ {x}^{2} + 6x + 5}{ { (x+ 3)}^{2} }$

$f'(2) = \frac{4 + 12 +5}{ {5}^{2} } = \frac{21}{25}$