Question

5a⁴-7b⁵+11c³ при a=2,b=-1,c=1​

Answer 1

$5 \times {2}^{4} - 7 \times {( - 1)}^{5} + 11 \times {1}^{3} = 5 \times 16 - 7 \times ( - 1) + 11 \times 1 = 80 + 7 + 11 = 98$