Question

2(x - 2) ≥ 3x +1
{
5(x + 1) ≤ 4x + 3
​

Answer 1

Ответ:

(-∞; -5]

{2(x - 2) ≥ 3x +1

{5(x + 1) ≤ 4x + 3

{2х-4 ≥ 3x +1

{5х+5 ≤ 4x + 3

{2х-3х ≥ 1+4

{5х-4х ≤ 3-5

{х ≤ -5

{х ≤ -2