Question

Помогите дам 40 баллов

Answer 1

$1)(x+y)^{2} +2x+2y+1=(x+y)^{2}+2(x+y)+1=(x+y+1)^{2} \\\\x=3,74 \ ; \ y=1,26\\\\(3,74+1,26+1)^{2}=6^{2}=\boxed{36}\\\\\\2)(27,3^{3}+16,7^{3}):(27,3^{2}-27,3*16,7+16,7^{2})=\\\\=(27,3+16,7)(27,3^{2}-27,3*16,7+16,7^{2}):(27,3^{2}-27,3*16,7+16,7^{2})=\\\\=27,3+16,7=\boxed{44}\\\\\\4)\frac{18^{3}+22^{3}}{(18-22)^{2}+18*22 }=\frac{(18+22)(18^{2}-18*22+22^{2})}{18^{2}-2*18*22+22^{2}+18*22}=\frac{(18+22)(18^{2}-18*22+22^{2})}{18^{2}-18*22+22^{2}}=\\\\=18+22=\boxed{40}$