Question

найди углы ABCD треугольника​

Answer 1

Ответ:

угол A =180-148= 32°

угол D = 180-55 = 125°

угол B = 180-125-32= 23°

Answer 2

Ответ:

$32^{\circ} \quad ; \quad 23^{\circ} \quad ; \quad 157^{\circ} \quad ; \quad 125^{\circ} \quad ;$

Пошаговое объяснение:

$\angle A=180^{\circ}-148^{\circ}=180^{\circ}-140^{\circ}-8^{\circ}=40^{\circ}-8^{\circ}=32^{\circ};$

$\angle D=180^{\circ}-55^{\circ}=180^{\circ}-50^{\circ}-5^{\circ}=130^{\circ}-5^{\circ}=125^{\circ};$

$\angle B=180^{\circ}-\angle A-\angle D;$

$\angle B=180^{\circ}-32^{\circ}-125^{\circ}=180^{\circ}-30^{\circ}-120^{\circ}-2^{\circ}-5^{\circ}=30^{\circ}-7^{\circ}=23^{\circ};$

$\angle C=180^{\circ}-\angle B;$

$\angle C=180^{\circ}-23^{\circ}=180^{\circ}-20^{\circ}-3^{\circ}=160^{\circ}-3^{\circ}=157^{\circ};$