Question

помогите пожалуйста решить ​

Answer 1

Ответ:

привести к общему знаменателю

Answer 2

$\frac{4x}{2x + 3} - \frac{2x}{2x - 3} = 1$

$\frac{4x \times (2x + 3)}{(2x + 3)(2x - 3)} - \frac{2x \times (2x - 3)}{(2x + 3)( 2x - 3) }= 1$

$\frac{8{x}^{2} + 12x }{4 {x}^{2} - 9} - \frac{4 {x}^{2} - 6x}{4 {x}^{2} - 9 } = 1$

$\frac{8 {x}^{2} + 12x - (4 {x}^{2} - 6x)}{4 {x}^{2} - 9 } = 1$

$\frac{8 {x}^{2} + 12x - 4 {x }^{2} + 6x}{4 {x}^{2} - 9} = 1$

$\frac{4 {x}^{2} + 18x }{4 {x}^{2} - 9 } = 1$

$4 {x}^{2} + 18x = 1 \times (4 {x}^{2} - 9)$

$4 {x}^{2} + 18x = 4 {x}^{2} - 9$

$4 {x}^{2} - 4 {x}^{2} + 18x = 9$

$18x = - 9$

$x = - \frac{9}{18} = - \frac{1}{2}$