Question

x^2-3y=13
x-y=3
С пояснением

Answer 1

${x}^{2} - 3y = 13 \brace x - y = 3 \\ {x}^{2} - 3y = 13 \brace 3x - 3y = 9 \\ {x}^{2} - 3x = 4 \brace y = x - 3\\ {x}^{2} - 3x - 4 = 0 \\ x_{1} + x_{2} = 3 \\ x_{1} \times x_{2} = - 4 \\ x_{1} = - 1 \: \: \: \: \: \: \: = > \: \: \: \: \: \: \: y_{1} = - 4 \\ x_{2} = 4 \: \: \: \: \: \: \: = > \: \: \: \: \: \: \: y_{2} = 1$