Question

arcsin(-√3/2)+arccos √2/2+arctg (-1)

Answer 1

Ответ:

$arcsin( - \frac{ \sqrt{3} }{2}) + arccos( \frac{ \sqrt{2} }{2}) + arctg( - 1) = \\ = - \frac{\pi}{3} + \frac{\pi}{4} - \frac{\pi}{4} = - \frac{\pi}{3}$