Question

[36] Решите уравнение:
(х-2)(х+2) -(x-3)^2=-1
СРОЧНО​

Answer 1

Ответ:

$(x - 2)(x + 2) - {(x - 3)}^{2} = - 1 \\ {x}^{2} - 4 - {x}^{2} + 6x - 9 = - 1 \\ 6x = - 1 + 13 \\ 6x = 12 \\ x = 2$