Question

Ал2Al+3H2SO4=2Al2 (SO4)3+3H2O

Answer 1

Mr(Al) - 27г

Mr(Al2(SO4)3) - 27×2 + (32+16×4)×3 = 342

54г(Al) = 342(Al2(SO4)3)

x г = 3,42 (Al2(SO4)3)

$x = \frac{54 \times 3.42}{342} = 0.54$

v = m/M = 0,54/27 = 0,02