Предмет: Химия, автор: meowthecheetah

Количество вещества фосфорной кислоты Н3РО4, порция которой содержит 1,806 •10^23 молекул.

Ответы

Автор ответа: saidamammadova1973

1

1моль__ 6,02•10²³

х моль____1,806•10²³

х= 1,806•10²³:6,02•10²³= 0,3 моль

Ответ:0,3 моль

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