Question

20 балов хелп фівавпвап

Answer 1

$2 {x}^{2} - 2x - 12$

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$a {x}^{2} + bx + c = 0$

Если x1 и x2 – корни уравнения, то

$a {x}^{2} + bx + c = a(x - x1)(x - x2)$

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$2 {x}^{2} - 2x - 12 = 0$

$d = {b}^{2} - 4ac = 4 + 96 = 100$

$x1 = \frac{ - b + \sqrt{d} }{2a} = \frac{2 + 10}{4} = \frac{12}{4} = 3$

$x2 = \frac{ - b - \sqrt{d} }{2a} = \frac{2 - 10}{4} = \frac{ - 8}{4} = - 2$

$2 {x}^{2} - 2x - 12 = 2(x - 3)(x + 2)$