Question

дам 50 баллов пожалуйста помогите​

Answer 1

Ответ:

$1)\ \ 2\sqrt2+3\sqrt2=5\sqrt2\\\\2\sqrt{a}+6\sqrt{a}-7\sqrt{a}=\sqrt{a}\\\\\sqrt{49x}-\sqrt{16x}+\sqrt{25x}=(7-4+5)\cdot \sqrt{x}=8\sqrt{x}\\\\\sqrt{32}+\sqrt{18}-\sqrt{50}=4\sqrt2+3\sqrt2-5\sqrt2=2\sqrt{2}$

$2)\ \ (1-\sqrt2)(3+\sqrt2)=3-2\sqrt2-2=1-2\sqrt2\\\\(\sqrt3+\sqrt7)(\sqrt3-\sqrt7)=3-7=-4\\\\(\sqrt2+\sqrt{10})^2=12+2\sqrt{20}=12+4\sqrt5\\\\(\sqrt{x}-\sqrt{y})^2=x+y-2\sqrt{xy}\\\\\\3)\ \ 6+\sqrt6=\sqrt6\cdot (\sqrt6+1)\\\\a^2-3=(a-\sqrt3)(a+\sqrt3)\\\\7-y=(\sqrt7-\sqrt{y})(7+\sqrt{y})\\\\16c^2-7=(4c-\sqrt7)(4c+\sqrt7)$