Предмет: Физика, автор: rita2311

Жесткость прорезиненного жгута 7,2 * 10 в четвертой степени Н/м. На какую длину растянется жгут, если на него действует сила 10кН?

Ответы

Автор ответа: Аноним

F =10кН = 10^4 H
k =7,2 * 10^4Н/м

L = F/k = 10^4 / 7,2 * 10^4 = 1/7.2 =0,139 м = 13,9 см

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