Предмет: Физика, автор: irinaalek

Определите электрическую емкость конденсатора ,если в его электрический заряд на обкладках равен 4*10^-4 Кл и он включен в цепь напряжением 200 в.

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Автор ответа: Аноним

Дано Q=4*10^-4 Кл U=200 В C-?
C= Q/U=4*10^-4/200=5*10^-6 Ф= 5 мкФ

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