Question

7-8 класс, 20 баллов

Answer 1

Ответ:

Объяснение:

1

$T = 2\pi \sqrt{\dfrac l g} \Rightarrow l = g\dfrac{T^2}{4\pi^2} = 10*\dfrac{1^2}{4*\pi^2} = 0.25~m$

2

$T_1 = \dfrac{\tau_0}{N_1} = 2\pi\sqrt{\dfrac{l_1} g} \Rightarrow l_1 = g\dfrac{\left(\dfrac{\tau_0}{N_1} \right)^2}{4\pi^2}\\T_2 = \dfrac{\tau_0}{N_2} = 2\pi\sqrt{\dfrac{l_2} g}\Rightarrow l_2 = g\dfrac{\left(\dfrac{\tau_0}{N_2} \right)^2}{4\pi^2}\\\dfrac{l_1}{l_2} = \dfrac{g\dfrac{\left(\dfrac{\tau_0}{N_1} \right)^2}{4\pi^2}}{g\dfrac{\left(\dfrac{\tau_0}{N_2} \right)^2}{4\pi^2}} = \dfrac{N_2^2}{N_1^2} = \dfrac{45^2}{15^2} = 9$

3

$\nu = \dfrac{3000}{60} = 50~Hz\\T = \dfrac 1 \nu = \dfrac{1}{50} = 0.02~s$