Question

3. реши уравнения плис помогите ​

Answer 1

Ответ:

$\frac{116}{125}-(\frac{41}{125}+x)=\frac{24}{125}\\\\\frac{116}{125}-\frac{41}{125}-x=\frac{24}{125}\\\\\frac{75}{125}-x=\frac{24}{125}\\\\ -x=\frac{24}{125} -\frac{75}{125} \\\\-x=-\frac{75-24}{125} \\\\-x=-\frac{51}{125}\\\\x=\frac{51}{125}$

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$\frac{4}{40}+y+ \frac{16}{40}=\frac{31}{40}+ \frac{6}{40}\\\\\frac{20}{40}+y=\frac{37}{40} \\\\y=\frac{37}{40}- \frac{20}{40}\\\\y=\frac{37-20}{40}\\\\y=\frac{17}{40}$

Пошаговое объяснение:

Answer 2

Ответ:

51/125; 17/40

Пошаговое объяснение:

116/125-(41/125+х)=24/125

116/125-24/125=41/125+х

92/125=41/125+х

х=92/125-41/125

х=51/125

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116/125-(41/125+101/125)=24/125

24/125=24/125

4/40+у+16/40=31/40+6/40

4/40+у+16/40=37/40

20/40+у=37/40

у=37/40-20/40

у=17/40

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4/40+17/40+16/40=31/40+6/40

37/40=37/40