Question

With the help of a cable, the tug pulls the barge in calm water. The barge moves evenly. What forces act on the barge and how do they relate?

Answer 1

Ответ:

Объяснение:

1

$F = ma \Rightarrow m = \dfrac F a = \dfrac{6}{0.15} = 40~kg$

2

b

Since the barge moves evenly, the resultant of the forces is zero, therefore the forces are equal to each other

3

a

similar to the previous question

4

$A = FS = mgS\\S_1 = \dfrac{gt_1^2}{2} = \dfrac{g(\dfrac{t}{2})^2}{2} = \dfrac{1}{4} \dfrac{gt^2}{2} = \dfrac 1 4 S\\S_2 = S - S_1 = \dfrac{3}{4}S\\\dfrac{A_1}{A_2} = \dfrac{mgS_1}{mgS_2} =\dfrac{mg\dfrac 1 4 S}{mg\dfrac 3 4 S} = \dfrac{1}{3}$