Question

501. a) (2x – 5)2 - 1 = 0;
6) (4y – 7)2 – (y + 2)2 = 0​

Answer 1

Ответ:

№1

(2x – 5)2 - 1 = 0;

4x-10-1=0

4x-11=0

4x=11

x=11:4

x=2.75

№2

(4y – 7)2 – (y + 2)2 = 0​

8y-14-2y+4=0

6y-10=0

6y=10

y=10:6

y=1.(6)