Question

Номер: 7, 102 бет
Пожалуйста срочно!
Даю 100 баллов​

Answer 1

$\frac{60}{90} -(\frac{6}{90} +x)=\frac{29}{90}\\\\\frac{60}{90}-\frac{6}{90}-x=\frac{29}{90} \\\\-x=\frac{29}{90} -\frac{60}{90} +\frac{6}{90}\\\\-x=-\frac{31}{90}+\frac{6}{90}\\\\-x=-\frac{25}{90}\\\\x=-\frac{25}{90}*(-1)\\\\x=\frac{25}{90}\\\\x=\frac{5}{18}$

Проверка:

$\frac{60}{90}-(\frac{6}{90}+\frac{5}{18})=\frac{29}{90}\\\\\frac{60}{90}-(\frac{6}{90} +\frac{25}{90} )=\frac{29}{90} \\\\\frac{60}{90}-\frac{31}{90}=\frac{29}{90}\\\\\frac{29}{90}=\frac{29}{90}$

Ответ:    $x=\frac{5}{18}$