Предмет: Геометрия, автор: bgdhbguehu

надо найти a b y
помогите пжпжжпжпжжпжп

Приложения:

Ответы

Автор ответа: 68tata
2

Ответ: 13 целых   91/150  ;   29/30    ;     90°  

Решение:

Острые углы прямоугольного треугольника равны 90°, поэтому

(β+19)°+(5α+2)°=90° .  

Так как а⊥с , а ║ b → b⊥c, то ∠Υ=90°

30β-11=β+19; как внутренние разносторонние углы при секущей

30β-β=19+11

29β=30

β∠=(29/30)°

5α+2° + (29/30)° +19° = 90°

5α= 90-21°-(29/30);

5α=68\frac{1}{30}

\alpha =\frac{2041}{30} *\frac{1}{5}=\frac{2041}{150} =13\frac{91}{150}


gfdjhiruiugrub: там не 3 а 30
gfdjhiruiugrub: 3β-11 а должно быть 30β-11
gfdjhiruiugrub: можешь исправить пожалуйста
68tata: да
gfdjhiruiugrub: спасибоооооооо
gfdjhiruiugrub: а как вышло с -150 30 градусов?
∠β=69°-5*= 69°-219°=-150°=30° вот тут
68tata: ПОКА РЕШАЕМ
gfdjhiruiugrub: ок
gfdjhiruiugrub: спасибоооо
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