Предмет: Физика, автор: 0pka

математический маятник длиной 1м совершает гармонические колебания с аплитудой 8 см определите скорость маятника при проходе им положения равновесия

Ответы

Автор ответа: fatt52

1

Ответ:

0,25 м/с

Объяснение:

А=0.08 м L=1 м g=9.8 м/с² v=?

===

T=2*π*√(L/g)

ω=2*π/T=√(g/L)

v=A*ω=A*√(g/L)=0,08*√(9,8/1)=0,25 м/с

==============================

0pka: спасибо

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