Предмет: Математика, автор: okmnenyshnapomoh

помогите мне с алгеброй

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Ответы

Автор ответа: Kari441

0

Ответ:

Пошаговое объяснение:

1)81y²-a^8=(9y-a^4)(9y+a^4)

0,49p^4-m²p^6=p^4(0,49-m²p²)=p^4(0,7-mp)(0,7+mp)

100x²-y^12=(10x-y^6)(10x+y^6)

1-64b^8=(1-8b^4)(1+8b^4)

2)125x³-27y³=(5x-3y)(25x²+15xy+9y²)

1+64y²=(1+4y)(1-4y+16y²)

m³/64+n³/125=(m/4+n/5)(m²/16-mn/20+n²/25)

8+1/8*a³=(2+1/2*a)(4-a+1/4*a²)

3)1-2a+a²=(1-a)²

4b²+28ab+49a²=(2b+7a)²

100m²+10mn+0,25n²=(10m+0,5n)²

1/4*a²-2ab+4b²=(1/2*a-2b)²

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