Question

помогите с интегралом!!​

Answer 1

$\int(4 {x}^{5} + \frac{7}{ \cos {}^{2} (3x) } - \frac{9}{4 \sqrt{x} } )dx = \int4 {x}^{5} dx + \int \frac{7}{ \cos {}^{2} (3x) } dx - \int \frac{9}{4 \sqrt{x} } dx = 4 \times \frac{x {}^{6} }{6} + 7 \int \frac{1}{ \cos {}^{2} (3x) } dx - \frac{9}{4} \int \frac{1}{ \sqrt{x} } dx = \frac{2 {x}^{6} }{3} + \frac{7}{3} \tg(3x) - \frac{9}{4} \times 2 \sqrt{x} = \frac{2 {x}^{6} }{3} + \frac{7}{3} \tg(3x) - \frac{9 \sqrt{x} }{2} + C$